fix: get tarball name as last line from stdout

Drapegnik · gr2m · commit cec807812ae4 · 2018-02-07T12:12:58.000-08:00
diff --git a/lib/publish.js b/lib/publish.js
@@ -11,7 +11,7 @@ module.exports = async ({npmPublish, tarballDir, pkgRoot}, {publishConfig, name}
 
   if (tarballDir) {
     logger.log('Creating npm package version %s', version);
-    const tarball = await execa.stdout('npm', ['pack', `./${basePath}`]);
+    const tarball = (await execa.stdout('npm', ['pack', `./${basePath}`])).split('\n').pop();
     await move(tarball, path.join(tarballDir.trim(), tarball));
   }
 

Original file line number	Diff line number	Diff line change
`@@ -11,7 +11,7 @@ module.exports = async ({npmPublish, tarballDir, pkgRoot}, {publishConfig, name}`
`11`	`11`
`12`	`12`	`if (tarballDir) {`
`13`	`13`	`logger.log('Creating npm package version %s', version);`
`14`		- const tarball = await execa.stdout('npm', ['pack', `./${basePath}`]);
	`14`	+ const tarball = (await execa.stdout('npm', ['pack', `./${basePath}`])).split('\n').pop();
`15`	`15`	`await move(tarball, path.join(tarballDir.trim(), tarball));`
`16`	`16`	`}`
`17`	`17`