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@leowzz leowzz commented Sep 21, 2023

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@gengjiawen
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@codeskyblue Can you take a look at this

var weight = f.type == 'dir' ? 1000 : 1;
return -weight * f.mtime;
var weight = f.type == 'dir' ? 'A' : 'a'; // 排序依据 文件名前缀
return weight + f.name.toUpperCase(); // 依据文件名
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2 participants