--accept-nth question

[097115]

As mentioned in 0.60.0 release notes

echo foo bar baz | fzf --accept-nth '1st: {1}, 2nd: {2}, 3rd: {3}'

should produce:

1st: foo, 2nd: bar, 3rd: baz

However, for me with fzf 0.63.0 (397fe8e) @ Ubuntu, the output is just foo bar baz. Same with the first example, echo foo bar baz | fzf --accept-nth 2, which should return bar -- for me again it returns foo bar baz.

The other related examples

echo foo,bar,baz | fzf --delimiter , --with-nth 1,3,..2 

and

echo foo,bar,baz | fzf --delimiter , --with-nth '{1},{3},{..2}'

work as advertised.

Am I missing something?

[nenahp]

Ensure you didn't set something in env, e.g.

echo foo bar baz | FZF_DEFAULT_OPTS= FZF_DEFAULT_OPTS_FILE= ./fzf --accept-nth '1st: {1}, 2nd: {2}, 3rd: {3}' --bind "enter:become:echo {}"

[097115]

Thanks, @nenahp! But no, for me the result is the same :)

And on your side, you can't reproduce it, right?

[junegunn]

And what do you get when you press enter?
(Without enter:become action of course as it will overrule the option)

[junegunn]

Your posting of that screenshot seems to suggest that you may have misunderstood the option. It does not change how an item is displayed in the list. It changes the output when you accept it by pressing enter key on it.

[097115]

@junegunn Thanks!

Indeed, I thought it would change the list, not the result :) Sorry for the mess, accepting the entry in fact returns 1st: foo, 2nd: bar, 3rd: baz.

Thanks again :)